How can we improve and make a more efficient nested if statement in javascript?

• /en/improve-nested-conditionals/

How can we improve and make a more efficient nested if statement in javascript?

if (color) {    if (color === 'black') {        printBlackBackground();    } else if (color === 'red') {        printRedBackground();    } else if (color === 'blue') {        printBlueBackground();    } else if (color === 'green') {        printGreenBackground();    } else {        printYellowBackground();    }}

One way to improve the nested if statement would be using the switch statement. Although it is less verbose and is more ordered, it’s not recommended to use it because it’s so difficult to debug errors. Here’s why.

switch (color) {    case 'black':        printBlackBackground();        break;    case 'red':        printRedBackground();        break;    case 'blue':        printBlueBackground();        break;    case 'green':        printGreenBackground();        break;    default:        printYellowBackground();}

But what if we have a conditional with several checks in each statement? In this case, if we want it less verbose and more ordered, we can use the conditional switch. If we pass true as a parameter to the switch statement, it allows us to put a conditional in each case.

switch (true) {    case typeof color === 'string' && color === 'black':        printBlackBackground();        break;    case typeof color === 'string' && color === 'red':        printRedBackground();        break;    case typeof color === 'string' && color === 'blue':        printBlueBackground();        break;    case typeof color === 'string' && color === 'green':        printGreenBackground();        break;    case typeof color === 'string' && color === 'yellow':        printYellowBackground();        break;}

If refactoring is an option, we can try to simplify the functions themselves. For example instead of having a function for each background color we could have an function that takes the color as an argument.

function printBackground(color) {    if (!color || typeof color !== 'string') {        return; // Invalid color, return immediately    }}

But if refactoring is not an option, we must always avoid having several checks in every condition and avoid using switch as much as possible. We also must take into account that the most efficient way to do this is through an object.

var colorObj = {    black: printBlackBackground,    red: printRedBackground,    blue: printBlueBackground,    green: printGreenBackground,    yellow: printYellowBackground};if (color in colorObj) {    colorObj[color]();}

Here you can find more information about this.